-10x^2-35x-15=0

Solution for -10x^2-35x-15=0 equation:

-10x^2-35x-15=0

a = -10; b = -35; c = -15;
Δ = b2-4ac
Δ = -352-4·(-10)·(-15)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-25}{2*-10}=\frac{10}{-20}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+25}{2*-10}=\frac{60}{-20}
=-3
$